extract --date="1 day" from today data (tomorrow)

This commit is contained in:
qo-op 2021-07-12 15:18:15 +02:00
parent dba2255cd1
commit a6254897a6
1 changed files with 4 additions and 4 deletions

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@ -19,10 +19,10 @@ D=$(echo "$SEM2" | awk -F 'au ' '{print $2}' | cut -d ' ' -f 1)
echo "SEMAINES: (1) $A - $B / (2) $C - $D"
DAY=$(date +%A | awk '{ print toupper( substr( $0, 1, 1 ) ) substr( $0, 2 ); }')
DOM=$(date +%-d) && TOM=$(($DOM + 1)) && ND=$(($DOM + 7)) # remove leading 0?
MONTH=$(date +%m)
YEAR=$(date +%y)
DAY=$(date +%A --date="1 day" | awk '{ print toupper( substr( $0, 1, 1 ) ) substr( $0, 2 ); }')
DOM=$(date +%-d --date="1 day") && TOM=$(($DOM + 1)) && ND=$(($DOM + 7)) # remove leading 0?
MONTH=$(date +%m --date="1 day")
YEAR=$(date +%y --date="1 day")
[[ $DAY == "Monday" ]] && DAY="Lundi" && DAYE="Mardi"
[[ $DAY == "Tuesday" ]] && DAY="Mardi" && DAYE="Mercredi"